A power plant burns 12 tons of coal per day to generate electricity. Each ton of coal produces 7,327 kWh of electricity and emits 0.75 pounds of CO2 per kWh. How many tons of CO2 are
emitted each day?

32.97 tons of CO2 per day.

Step-by-step explanation:

From the question given above, the following were obtained:

Power plant burns = 12 tons of coal per day

1 ton of coal = 7327 kWh

CO2 emitted = 0.75 pound per kWh

Tons of CO2 emitted per day =?

Next, we shall convert 0.75 pound to ton.

This can be obtained as follow:

2000 pounds = 1 ton

Therefore,

0.75 pound = 0.75 pound/2000 pounds × 1 ton

0.75 pound = 3.75×10¯⁴ ton

Therefore, 0.75 pound is equivalent 3.75×10¯⁴ ton.

From the above, we can say that CO2 is emitted at 3.75×10¯⁴ ton per kWh.

Next, we shall determine the electricity generated per day.

This can be obtained as follow:

1 ton of coal = 7327 kWh of electricity

Therefore,

12 tons of coal = 12 × 7327

12 tons of coal = 87924 kWh of electricity.

Therefore, the plant produces 87924 kWh of electricity per day.

Finally, we shall determine the tons of CO2 emitted per day as follow:

1 kWh of electricity emitts 3.75×10¯⁴ ton of CO2.

Therefore, 87924 kWh of electricity will emitt = 87924 × 3.75×10¯⁴ = 32.97 tons of CO2 per day.

From the calculations made above, the pant emitts 32.97 tons of CO2 per day.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it