Compute the Taylor expansion of order n=2 of the function sin(xy) at x=0 and y=0

f(x, y) = Sin(x*y)

We want the second order taylor expansion around x = 0, y = 0.

This will be:

So let's find all the terms:

Remember that:

f(0,0) = sin(0*0) = 1.

Then we have that the taylor expansion of second order around x = 0 and y = 0 is:

sin(x,y) = x*y + x*y + x*y = 3*x*y

it 2

step-by-step explanation:

8^1/3=2

a

step-by-step explanation: