Solve: |4x + 2| < 8 help me please

-5/2 < x < 3/2

In interval notation: (-5/2, 3/2)

Step-by-step explanation:

Rule

To solve an absolute value inequality of the form

|X| < k

where X is an expression in x and k is a non-negative number,

solve the following compound inequality

-k < X < k

For this problem, X is 4x + 2, an expression in x. k is 8.

Follow the rule above, and change the absolute value inequality

|4x + 2| < 8 into

-8 < 4x + 2 < 8

Now we solve the compound inequality.

Subtract 2 from the three sides.

-10 < 4x < 6

Divide the three sides by 4.

-10/4 < x < 6/4

Reduce the fractions.

-5/2 < x < 3/2

-5/2 < x < 3/2

In interval notation: (-5/2, 3/2)

or

Step-by-step explanation:

To get the fraction

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

ha!

i just did this!

18. g

20. h 30 degree turn.

21. d 90 degree angles

and also 19 is a. a sphere not a cirlcle

hope i !

pls mark me brainiest