In a triangle, the measure of the first angle is 24 degrees more than the measure of the second angle. The measure of the third angle is four times the measure of the second angle. If the total numbet of degrees in a triangle is 180, what is the measure of the largest angle?

104°

Step-by-step explanation:

let the second angle be x , then

the first angle is x + 24

the third angle is 4x , thus summing and equating to 180

x + x + 24 + 4x = 180, that is

6x + 24 = 180 ( subtract 24 from both sides )

6x = 156 ( divide both sides by 6 )

x = 26

Thus largest angle = 4x = 4 × 26 = 104°

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

im not sure

step-by-step explanation: