Let f(x)=x^2+2 and g(x)=2x, find (fog)( x)

Step-by-step explanation:

f(x) = x² + 2

g(x) = 2x

To find (fog)( x) substitute g(x) into f(x) that's for every x in f (x) replace it with g (x)

We have

(fog)( x) = ( 2x)² + 2

We have the final answer as

Hope this helps you

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.