the father divide a number of his cows to his thee sons Mongo, masuu and muzo a half of it was given to Mongo and 3/4 of the remaining to musuu while muzo get the remaining which were 25cows. find cows were distributed

Original number of cow = 200
Mongo receive = 100 cow
Masuu receive = 75 cow
Muzo receive = 25 cow

Explanation:

Let x be the original number of cow:

And x = 100%

Mongo = x/2 = 100%/2 = 50%

Thus, mongo receive 50% of the cow and the other 50% are divide to masuu and muzo.

50% = 3/4 + 1/4

Where 3/4 was given to masuu and 1/4 was given muzo.

But muzo receive 25 cow as a remaining thus, 1/4 = 25

If 1/4 = 25 then 3/4 = 75

Therefore, 50% = (75 + 25)cow
50% = 100 cow

But Mongo receive half of the original cows. Which mean he receive 100 cows.

Original number of cow = 100 + 75 + 25 = 200 cows

What are the options