Solve: 2x+p/q = 2x+q/p If p=q, if p cannot equal to q

p= -q

Step-by-step explanation:

(2xq+p)/q= (2xp+q)/p

After cross multiplying,

2xpq+p²= 2xpq+q²

p²=q²

p²-q²=0

(p+q)(p-q)=0

either p+q=0 : p= -q

or p-q=0 : p=q which is not possible because of the given condition

Thus, the only solution of this equation is:

p= -q

b

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.