Identify the zeros of the function f(x) = x2 + 16.

no real zeros

imaginary zeros : ±4i

Step-by-step explanation:

f(x) = x^2 + 16

Set equal to zero

0 = x^2 +16

Subtract 16 from each side

-16 = x^2

We have no real zeros

We have imaginary zeros

Taking the square root of each side

sqrt(-16) = sqrt(x^2)

±4i = x

p> q if you calculate p is100 q is 79

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb