Did I pick the right answer?

The second answer is the right one

Step-by-step explanation:

Let a be the average rate of change in the interval [0,4] for the function A

● a = (16-0)/(4-0) = 16/4 = 4

The average rate of change in [0,4] is 4 for the function A

Let b be the averagerate of change in [0,4] for the function B

● f(4) = 2×4-1 = 8-1 = 7

● f(0) = 2×0 -1 = -1

● b = (f(4)-f(0))/(4-0)= (7-(-1))/4 = 8/4 = 2

So the average rate of change in[0,4] is 2 for the function B

A=4 , B=2

Step-by-step explanation:

The average rate of change of f(x) on the interval [a,b] is :f(b)−f(a)/b−a.

for equation A: f(x)=x²

f(0)=0²=0

f(4)=4² =16

average rate = (4²-0²)/4-0=16/4=4

average rate for equation B : f(x)=2x-1

f(0)=2(0)-1 = -1

f(4)=2(4)-1=7

average rate :7-(-1)/4-0 = 8/4 = 2

step-by-step explanation:

he kicked it up? is this the answer ?

step-by-step explanation: