Two perpendicular lines PQ and QR intersect at (1, -1). If the equation of PQ is x - 2y + 4 = 0, find the equation of QR.

2x + y - 1 = 0

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

x - 2y + 4 = 0 ( subtract x + 4 from both sides )

- 2y = - x - 4 ( divide all terms by - 2 )

y = x + 2 ← in slope- intercept form

with slope m =  

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 2 , thus

y = - 2x + c ← is the partial equation of the perpendicular line

To find c substitute (1, - 1) into the partial equation

- 1 = - 2 + c ⇒ c = - 1 + 2 = 1

y = - 2x + 1 ← in slope intercept form

Subtract - 2x + 1 from both sides

2x + y - 1 = 0 ← in general form

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

answer: entity is prob the answer

step-by-step explanation: