A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the function H(t)=−4.9t2+25t+2. What is the height of the ball at each second from 0 to 5? t 0 1 2 3 4 5 H 0 20.1 30.4 30.9 21.6 2.5 t 0 1 2 3 4 5 H 2 27 52 77 102 127 t 0 1 2 3 4 5 H 2 22.1 42.2 62.3 82.4 102.5

Step-by-step explanation:

A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the function as follows:

We need to find the height of the ball from 0 to 5 seconds

At t = 0 s

At t = 1 s

At t = 2 s

At t = 3 s

At t = 4 s

At t = 5 s

t =  0         1                2                3                4                 5

H = 2       22.1         32.4         32.9           23.6           4.5

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

the answer is 48m^2!

step-by-step explanation: