Find the coordinates of P(a, b) whose ordinate is twice as much as abscissa and sum of coordinates is -12.

P(- 4, - 8 )

Step-by-step explanation:

The abscissa is the x- coordinate and the ordinate is the y- coordinate.

Here b = 2a , thus

a + 2a = - 12

3a = - 12 ( divide both sides by 3 )

a = - 4

and b = 2a = 2 × - 4 = - 8

P(- 4, - 8 )

h/o/e/s mad

step-by-step explanation:

si si si

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4