Just need help with the 3 bullet point at the bottom!! In the same way that other functions can be combined, a series of transformations can be combined into a single
function. For example, this statement for the function S shows one way to represent the rotation of a point 270"
counterclockwise about the origin followed by a translation 3 units to the left and 1 unit up: S(270, 0)/43,1>0, y) = (y-
3, -x + 1)
Write a function to represent each series of transformations,
• rotation of 90 degrees counterclockwise about the origin, point o, then a reflection across the waxis
• reflection across the y axis, then a translation a units to the right and b units up
• translation a units to the right and bunits up, then a rotation of 180 degrees counterclockwise about the origin,
then a reflection across the y-axis

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

4932,9180,7625 are divisible by 9

one way is to plot 2 points and connect them which is what the answer choices seem to be doing

it seems to be using the y intercept and the slope

y=mx+b, m=slope, b=y-intercept (where the line hits the y axis)

slope=rise/run

y-intercept is where the line croses the y axis which is the y value where x=0

you seem to have given the wrong slope (you didn't put a number in front of te x, it should be 2/3 or 3/2 looking at the answer options)

y=? x-1

m=? because of your fault

b=-1

so it has a slope of ? and y intercept of -1, meaning it pases through (0,-1)

so draw point (0,-1) (so answer is one of the first 2 option)

if slope is 2/3, then go up 2 and right 3 then draw line through those 2 points

if slope is 3/2, then go up 3 and right 2 then draw line through those 2 points