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Mathematics, 05.09.2020 20:01 angelaOR

\begin{aligned} A.&&5&=-2(x-1) B.&&5&=-2x+2 \end{aligned} A. B. 5 5 =βˆ’2(xβˆ’1) =βˆ’2x+2 1) How can we get Equation BBB from Equation AAA?

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\begin{aligned} A.&&5&=-2(x-1) B.&&5&=-2x+2 \end{aligned} A. B. 5 5 =βˆ’2(...
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