Trent train is traveling at the speed of 10m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is moving at 39 m/s. What is the rate of acceleration of Trent train?

The first thing to do before starting to solve any numerical is to write down all the information we have.

Initial speed (u) = 10 m/s

Final speed  (v) = 39 m/s

Time (t) = 5 seconds

To find acceleration(a):

We know the equation for the first Law of Motion:

v = u+a*t

Hence, we can rearrange this as:

a = (v-u)/t

On substituting the values given,

a = (39 - 10)/5

a = 29/5

a = 5.8 m/(s^2)

Hence, the acceleration of the train is 5.8 m/(s^2)

idk this answer sorry cant on this one.

step-by-step explanation:

square pyramid

step-by-step explanation:

square prism looks like nothing like that

triangular prism has a rectangular base instead of a square base

tetrahedron has a triangular base