Triangle ABC has vertices at A(-3, 1), B(2, -4), and C(1, 5). It is translated 2 units right and 3 units down to form triangle A’B’C’. A'B'C' is then reflected over the line y = x to form triangle A''B''C''. What are the vertices of triangle A’'B’'C’'? A. A''(2, 1), B''(7,-4), C''(-2, 3) B. A''(2, -1), B''(7,4), C''(-2, -3) C. A''(-1, -2), B''(4,-7), C''(-3, 2) D. A''(-2, -1), B''(-7,4), C''(2, 3)

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

just keep asking questions until you have a better understanding.

step-by-step explanation: