Why is√5 irrational? A.)because it is less than one
B.)because it has no opposite
C.)because all square roots are irrational
D.)because it cannot be expressed as a ratio of integers

The expression x(x + 1) is even for any integer x (since either x or x + 1 is even). So this says that 5 × even + 1 = even, or odd = even. Since there is no integer that is both even and odd, we have reached a contradiction and √5 is irrational. So the answer would be D.) because it cannot be expressed as a ratio of integers

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step-by-step explanation:

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1