suppose the equation for line A is given by 2x-5y=15, if line A and B are parallel and the point (-10,3) lies on line B, then write the equation in slope intercept for line b.

y=2/5x + 7

Step-by-step explanation:

First, you have to rewrite 2x-5y=15 to slop intercept form.

To do that you have to first subtract 2x from both side to cancel it out.

2x- 2x-5y= 15 -2x.    

-5y= -2x+15

Next, you divide 5 on both side to leave the y by itself.

y= -2x/-5 + 15/-5

Simplify

y= 2/5x + (-3)                     2/5 is our slope

Now that we found the slope, we need to the y-intercept of line b

y=2/5x + b

To find the y-intercept, we substitue x and y with the coordinates (-10,3)

3= 2/5(-10) +b

Now we just solve for b

3= -4 +b

3-(-4) = b

7=b

Now we have identified that 7 is the y intercept

The full equation is y= 2/5x +7

I hope this helped :)

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.