The point P(4, −2) lies on the curve y = 2/(3 − x). (a) If Q is the point (x, 2/(3 − x)), use your calculator to find the slope mPQ of the secant line PQ (correct to six decimal places) for the following values of x. (i) 3.9 mPQ = (ii) 3.99 mPQ = (iii) 3.999 mPQ = (iv) 3.9999 mPQ = (v) 4.1 mPQ = (vi) 4.01 mPQ = (vii) 4.001 mPQ = (viii) 4.0001 mPQ = (b) Using the results of part (a), guess the value of the slope m of the tangent line to the curve at P(4, −2). m = (c) Using the slope from part (b), find an equation of the tangent line to the curve at P(4, −2).

its kind of blurry. can you put a clearer pic?

step-by-step explanation:

i think it is 18

step-by-step explanation:

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)