Find the distance from D (-6, -2) to T (7,-8)

(13, 6)

Step-by-step explanation:

Step 1:

Make turn everything into absolute value. Which makes it positive.

Step 2:

6 = 7 = 13

Step 2:

8 - 6 = 4

(13, 6)

Hope This Helps :)

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.