Find three consecutive integers have a sum of -36 what is the largest integer

3 consecutive integers : x, x + 1, x + 2

x + (x + 1) + (x + 2) = - 36...combine like terms
3x + 3 = -36...subtract 3 from both sides
3x = -36 - 3
3x = - 39divide both sides by 3
x = -39/3
x = - 13

x + 1 = -13 + 1 = -12
x + 2 = -13 + 2 = -11

the largest integer would be -11

Answer: r=4.5  feetexplanation: radius  r  is half of the diameter  d,⇒r=d2=92=4.5  feetidk i could be wrong