Use inverse operations to find the inverse of y = 27x?
The inverse of y = 27x3 is y =

  y = (∛x)/3

Step-by-step explanation:

To undo the multiplication by 27, you multiply by its inverse:

  (1/27)y = (1/27)(27x^3)

  y/27 = x^3 . . . . . . . . . . . simplify

To undo the cube, you take the cube root:

  (∛y)/(∛27) = ∛(x^3)

  (∛y)/3 = x

Apparently, you want the inverse function, so you swap the variables:

  y = (∛x)/3

You can swap the variables at the beginning or end. It doesn't matter. If you do it at the beginning, you have ...

  x = 27y^3

and you're solving for y. You use the same inverse operations that we used above.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

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step-by-step explanation: