Tim has a bag of 36 orange-flavored sweets and Peter has a bag of 44 grape-flavored sweets. They have to divide up the sweets into small trays with equal number of sweets; each tray containing either orange-flavored or grape-flavored sweets only. If there is no remainder, find the largest possible number of sweets in each tray.

The largest possible number of sweets in each tray is 4.

In order to determine the largest possible sweets in each tray, the highest common factor of the number of sweets have to determined. The highest common factor is the highest factor that is common to two or more numbers.

Factors of 36 =  1, 2, 3, 4, 6, 9, 12, 18, and 36.

Factors of 44 = 1, 2, 4, 11, 22, 44.

Common factors = 1, 2, 4

Highest common factor - 4  

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Largest possible number of sweets in each tray

Step-by-step explanation:

Given:

Number of orange-flavored sweets = 36

Number of grape-flavored sweets = 44

To find: largest possible number of sweets in each tray

Solution:

HCF(highest common factor) of two or more numbers refers to the greatest number which can divide the given numbers

To find largest possible number of sweets in each tray, find the HCF(highest common factor) of 36 and 44.

So,

So,

Largest possible number of sweets in each tray

1; 35 is the ratio

step-by-step explanation:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: