Consider a rectangle with width of x units and an area of 10 square units. The length l of the rectangle can be modeled by the function f (x) = StartFraction 10 Over x EndFraction.

When we have a rectangle of width W and length L, the area of this rectangle can be calculated as:

A = W*L

In this case we have:

W = x

L = 10/x.

Then the area of the rectangle will be:

A = W*L = x*(10/x) = 10

So the value of x cancels in the equation, which means that we can not find the value of x.

Now, as L = 10/x we can find some restrictions:

if x = 0, we would have L = 10/0

So we can not have x = 0.

And as W = x, this represents a positive measure, we also have that x can not be a negative number.

So the relation:

W = x

L = 10/x

Gives us all the possible combinations of width and length such that the area of the rectangle is exactly 10 square units.

da freeck kinda math is this just drop out

step-by-step explanation:

answer: 414,377,008

step-by-step explanation:

just multiply it