The sum of three numbers is 45. The second of the three numbers is three more than twice the first number, x. The third number is two more than the first number, x. Which equation can be used to solve for the first number, x?
Ox+ 5x + x + 2 = 45
O x + x + 3 + x + 2 = 45
O x + 3x + 2 + x + 2 = 45
O x + 2x + 3 + x + 2 = 45

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

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the answer would be c