If the square root of a number is equal to twice the same number what is the number?

Step-by-step explanation:

let the number be x , then

= 2x ( square both sides )

x = (2x)² = 4x² ( subtract x from both sides )

4x² - x = 0 ( factor out x from each term )

x(4x - 1) = 0

Equate each factor to zero and solve for x

x = 0

4x - 1 = 0 ⇒ 4x = 1 ⇒ x =

Assuming x > 0 then the number is

As a check

= and 2 × =

d. is the correct answer

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2