car A leaves at 8:00am at 40mph car B leaves 2 hours later at 60mph how long does it take car B to catch up to car A?

4hrs

car b started at 10am

at 10am car a is already at (40×2hrs)=80m

11am:

a- 80+40=120m

b-0+ 60=60m

12am:

a-120+40=160m

b-60+60=120m

1pm:

a-160+40=200m

b-120+60=180m

2pm:

a-200+40=240m

b-180+60=240m

car B caught up with car A at 2pm

so from 10am to 2pm= 4 hrs

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75