A rare bacterial culture is being grown in a lab. As time passes, cells multiply in a specific pattern. After 1 day, there is only 1 cell. After 2 days, there are 5 cells. After 3 days, there are 10 cells. After 4 days, there are 16. How many cells will there be after seven days? A. 40 B. 50 C. 70 D. 70

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

answer: 193

explanation:

200-7 = 193