Please help I've been stuck on this for a while

x=5,y=2,z=-1

Step-by-step explanation:

x+y+z=6 1

2x-y+3z=5 2

3x+2z=13 ⇒3x=13+2z ⇒ x=(13-2z)/3

substitute for x in equation 1 and 2

13-2z/3+y+z=6 ⇒13/3 -2z/3+y+z=6 ⇒z/3+y=6-13/3

2(13-2z)/3-y+3z=5

26/3-4z/3-y+3z=5⇒5z/3-y=5-26/3⇒

5z/3-y+z/3+y=-11/3+5/3

6z/3=-6/3

x=(13+2)/3

5+y-1=6

y=6+1-5

42

step-by-step explanation:

256/6=42

529 and 531

step-by-step explanation: