A car of m = 1200. kg collides with a tree while traveling 60.0 mph. The collision occurs over a time period of 0.0500 seconds. Determine the magnitude of the force exerted on the car as it comes to rest during the collision. (1 m/s = 2.24 mph) 1.58 × 10 3N 1.44 × 10 6N 3.60 × 10 3N 6.4331 × 10 5N

6.4331 × 10 5N

Step-by-step explanation:

Given the following :

Mass (m) of car = 1200kg

Initial Velocity (u) of car = 60 mph

Final velocity = 0 ( comes to rest)

Velocity in m/s = 60 / 2.24 = 26.785 m/s

Time (t) = 0.0500

Using the relation :

Ft = m(v - u)

Where,

v = final velocity ; u = initial velocity ; t = time ; F = force

F*0.05 = 1200(26.785 - 0)

0.05F = 32142.86 - 0

F = 32142.86 / 0.05

F = 642857.14 N

F = 6.43 × 10^5 N

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

30 people weigh 160 pounds or more