A new Youth Sports Center is being built in Hadleyville, The perimeter of the rectangular playing field is 430 yards. The length of the field is 5 yards the width. What are the dimensions of the playing field?

The width is

yards

The length is

yards

Width = 44 yards

Length = 171 yards

Step-by-step explanation:

given data

length of the field = 5 yards

Perimeter of the rectangular field = 430 yards.

solution

we consider here length of the field = L

and width of the field = W

as we know length of the field 5yards less than quadruple the width

so here

L = 4W - 5       1

and  

Perimeter (P) will be here

P = 2(L + W)      2

put here equation 1 value

430 = 2(4W - 5 + W)  

solve it we get

W = 44

so here put value in eq 1 we het

L = 4W - 5          

L = 4(44) - 5

L = 171

so, length of the field is 171 yards

i believe the answer is letter c) 8

step-by-step explanation:

w'x is 0.

hope it