I need help please! If m∠ABD=76°, what are m∠ABC and m∠DBC? If m∠JKH=77° then m∠NDF=__

m<ABC = 41°

m<DBC = 35°

m<NDF = 77°

Step-by-step explanation:

Problem 1:

Given, m<ABD = 76°, m<ABC = (7x - 1), m<DBC = (5x + 5)

m<ABC + DBC = m<ABD (angle addition postulate)

(substitution)

Solve for x

Collect like terms

Subtract 4 from each side

Divide each side by 12

Find m<ABC

m<ABC = (7x - 1)

Plug in the value of x

m<ABC = 7(6) - 1 = 42 - 1 = 41°

Find m<DBC

m<DBC = (5x + 5)

Plug in the value of x

m<DBC = 5(6) + 5 = 30 + 5 = 35°

Problem 2:

<JKH and <NDF are corresponding angles. Corresponding angles are congruent.

Given that m<JKH = 77°, m<NDF = 77° (corresponding angles are equal).

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

r and t.

both are 64 degrees.