What are the roots of the equation 4x^2 + 16x + 25 = 0 in simplest a + bi form?

-2 + 3i/2, and -2-3i/2

Step-by-step explanation:

Apply the quadratic formula.

We have (-16 +-sqrt(16^2-4*4*25))/8.

Simplifying, we have (-16+-12i)/8.

Thus, the roots are -2 + 3i/2, and -2-3i/2

The roots are

Step-by-step explanation:

4x² + 16x + 25 = 0

Using the quadratic formula

That's

From the question

a = 4 , b = 16 , c = 25

Substitute the values into the above formula and solve

We have

Separate the real and imaginary parts

That's

We have the final answer as

Hope this helps you

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.