What is the factor to dilate triangle ABC to get A'B'C'? (Write your answer below. Show your work for partial credit.)

The Factor is 1.5

Step-by-step explanation:

5.1(which is B'C') divided by 3.4(which is BC) = 1.5

3.6(A'C') divided by divided by 2.4(AC) = 1.5

2.7(A'B') divided by 1.8(AB) = 1.5

Henceforth the factor is 1.5  

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.