I’ve done this 3 different way and I’m still getting it wrong someone help I feel dumb

note: remember to take the comma out or ignore it. I put it in there to help make the number more readable

Explanation:

Let x be the value of the sale in dollars.

x-1900 represents the leftover amount that is over 1900

eg: if x = 2200, then x-1900 = 2200-1900 = 300 is the the leftover amount

taking 9% of (x-1900) leads to the expression 0.09(x-1900) and this expression must be 1000 since this is the extra amount of money the salesman needs (he already has $1000 in base pay)

Solve for x

0.09(x-1900) = 1000

x-1900 = 1000/0.09

x-1900 = 11,111.11111 approximately

x = 11,111.11111 + 1900

x = 13011.1111

x = 13,011.11 rounding to the nearest cent

you're missing vital information, add to it so we can solve this problem for you.

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2