Part A: Maci made $170 grooming dogs one day with her mobile dog grooming business. She charges $60 per appointment and earned $50 in tips. Write an equation to represent this situation. (4 points) Part B: Logan made a profit of $210.00 as a mobile groomer. He charged $75.00 per appointment and received $35.00 in tips, but also had to pay a rental fee for the truck at $10.00 per appointment. Write an equation to represent this situation. (4 points) Part C: Explain how the equations from Part A and Part B differ. (2 points)

c is the answer

step-by-step explanation:

answer: 10 meter

step-by-step explanation:

need details

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

10+4√2 is the answer. i dont have the time to explain.