A 2.5 ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles. The radius of the inner circle is ft. How much farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn?

15.71 ft

Step-by-step explanation:

Given that:

width of the circular track = 2.5ft

Suppose the radius of the inner circle is 57 ft since it is not given

Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft

The circumference of a circle = 2πr

For inner circle now, the circumference = 2 × π × 57 ft

For inner circle now, the circumference = 358.14 ft

For the outer circle, the circumference = 2 × π × 59.5 ft

For the outer circle, the circumference = 373.85 ft

The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn

∴

= ( 373.85 - 358.14 ) ft

= 15.71 ft

where's the diagram?

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: