Explain why a quadratic equation with a positive discriminant has two real solutions, And why a quadratic equation with a negative discriminant has no real solution, And a quadratic equation with a discriminant of zero has one real solution.

The given equation is -2x^2 = -8x + 8

This can be rewritten as 2x^2 - 8x + 8 = 0

Here the value of a =2, b = -8 and c = 8

Discriminant = b^2 - 4ac

Now plug in the above values in the discriminant, we get

= (-8)^2 - 4*2*8

= 64 - 64

= 0

Here the discriminant is 0, so we will get one real root.

The discriminant is equal to 0, which means the equation has one real number solution.

Hope this will helpful.

Thank you.

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step-by-step explanation:

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