The area of four walls of a rectangular room is 96m2 and its height is 4m. Calculate the perimeter
of the floor of the room,

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

To find the area we must first find the length of the rectangle using it's area.

That's

Area = length × height

From the question

Area = 96 m²

height = 4 m

So we have

96 = 4l

Divide both sides by 4

length = 24 m

Now we have

Perimeter = 2(24) + 2(4)

= 48 + 8

We have the final answer as

Hope this helps you

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3