Suppose that we have a pair of random variables X and Y with joint distribution X
2 4 6
2 0.04 0.02 0.04
Y 4 0.12 0.06 0.12
6 0.24 0.12 0.24
(a) If we have M = max(X Y) the larger of the two observations, then calculate P{M = 6}.
(b) Show that X ami Y are independent.

P (m=6)= 0.60

Marginal probability of y=  0.4 , 0.2 and 0.4

Marginal probability of x= 0.1  0.3 and 0.6

Step-by-step explanation:

The data given is

     X      2             4              6    

      2     0.04       0.02         0.04

y     4     0.12        0.06         0.12

     6      0.24      0.12          0.24

So the maximum value  M= max (X Y) is  (2,6) (6,4)(6,6)

We pick the larger value for each of the two observations

P (m=6) = 0.24+ 0.12+  0.24= 0.60

  X      2             4              6             Marginal

      2     0.04       0.02         0.04      0.1

y     4     0.12        0.06         0.12       0.3

      6      0.24      0.12          0.24      0.6

M.            0.4       0.2            0.4          1

The total is always equal to 1 .

X and Y are independent as the product of the marginal probability gives the joint probability.

We find the marginal probability by adding the rows and columns and then check if their product equal the given joint distribution which is true.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.