Express in terms of the unit step function, the piecewise continuous causal functions () = { 2 2 , 0 ≤ < 3 + 4, 3 ≤ < 5 9, ≥ 5 [3 marks] ii. Use Laplace transforms to solve the initial value problem ) ′′ + 16 = 43 + ( − ⁄3) where (0) = 0 and ′(0) = 0.

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute:

acd, jgvjgbgbgvhgbhjjn

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

is the anwser b. (-13)?