Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 56.6 degrees. Low Temperature (◦F) 40−44 45−49 50−54 55−59 60−64 Frequency 2 7 9 5 2 The mean of the frequency distribution is nothing degrees.

Computed mean = 51.6

Actual mean > computed mean

Step-by-step explanation:

Low temp. - - Freq(f) - - midpoint(x) - - fx

40−44 - - - - - 2 - - - - - - - 42 - - - - - - 84

45−49 - - - - - 7 - - - - - - - 47 - - - - - - 329

50−54 - - - - - 9 - - - - - - - 52 - - - - - - 468

55−59 - - - - - 5 - - - - - - - 57 - - - - - - 285

60−64 - - - - - 2 - - - - - - - 62 - - - - - - 124

Mean (m) = Σ(fx) / Σ(f)

Σ(fx) = 84 + 329 + 468 + 285 + 124 = 1290

Σ(f) = 2 + 7 + 9 + 5 + 2 = 25

Mean (m) = 1290 / 25

Computed mean (m) = 51.6

Actual mean = 56.6

Actual mean > computed mean

56.6 > 51.6

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

the answer will be b x² +x-1

step-by-step explanation: