4. The Ferris Wheel Problem: You are riding a Ferris wheel that has a radius of 50 feet. The center of the wheel is
65 feet off the ground. The wheel makes a complete turn every 40 seconds and it
turns counterclockwise, Riders board the wheel at the 6 o'clock position
You can see a beautiful view from the Ferris wheel as long as you are more than 90
feet off the ground. When will you be able to see the view
acer

the answer is when the wheel is at 70.43° after 7.82seconds from when you ride on it

Step-by-step explanation:

Rule of 3

65ft center meaning the top point at 90° will be at 115ft since the diameter of the wheel is 50ft

If the 90° gets you at 115ft, at what degree will you reach 90ft?

90°115ft

X°90ft

(90x90) ÷ 115 = 70.43°

Then if 360° takes 40seconds which is the complete turn

360°40s

70.43°--X

(70.43 x 40) ÷ 360 = 7.82s

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

step-by-step explanation: