22. Find three consecutive odd numbers such that the sum of five times the smaller number and twice the larger number is 33 more than six times the median number.

The numbers are 37, 39 and 41.

Step-by-step explanation:

Let the smallest number be .

Then the other numbers will be (as they are consecutive odd numbers, their difference will be 2).

As per the given statement:

LHS(Left Hand Side) : Sum of five times the smaller number and twice the larger number.

i.e. five times the smaller number =

twice the larger number =

Their sum:

The Left Hand Side becomes:

RHS(Right Hand Side):

33 more than six times the median number:

i.e.

Equating LHS and RHS:

Therefore, the numbers are 37, 39 and 41.

answer: i can’t tell you that

step-by-step explanation:

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew