Describe and correct the error a student made in finding the interval(s) over which the function is positive and negative. LOADING... Click the icon to view the student's work.
Choose the correct answer below.
A.
The zeros are neither positive nor negative. The student included these in the interval over which the function is negative, which is incorrect.
B.
The zeros are both positive and negative. The student included these in the interval over which the function is positive but not in which the function is negative, which is incorrect.
C.
The zeros are neither positive nor negative. The student included these in the interval over which the function is positive, which is incorrect.
D.
The zeros are negative. The student included these in the interval over which the

96 39 cause 135 -96=39 im smart (i used a calculater)

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt