What is the area of this irregular figure?

hey man if you figure this out comment back bc i need to know also. sorry and thanks!

Step-by-step explanation:

A=192cm^2

Step-by-step explanation:  Cut the shape. You now have Shape A and B.

Shape A is 8x8=64cm.

Shape B is 16x8=128cm

128cm+64cm= 192^2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.