A whale that is 460 feet below sea level rises up and breaches out of water to a height of 27 feet above sea level. What is the vertical distance the whale travels.

Step-by-step explanation:

Let the initial point of of the sea level be 0. If the whale was initially 460 feet below sea level, then its distance from the surface of sea level to the 460ft below the sea level will be 460 - 0 = 460ft.

Also, if the whale rises up and breaches out of water to a height of 27 feet above sea level, then its distance from the surface of sea level to the 27ft above the sea level will be 0 - 27 = 27ft.

The vertical distance that the whale travels = distance from the sea level to 460ft below the sea level + distance from the sea level to 27ft above the sea level

The vertical distance that the whale travels  = 460ft + 27ft

The vertical distance that the whale travels  = 487ft

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form