Find the equation of a line that is perpendicular to the line -2y+20=8x and passes through the point (7,2).

  8y -2 = 2x

Step-by-step explanation:

The equation of the perpendicular line will have the coefficients of x and y swapped, and one of them negated. The constant can be found by substituting the given point value:

  8y +constant = 2x . . . . coefficients swapped; former y-coefficient negated

  8(2) +constant = 2(7) . . . . . fill in given point values (x, y) = (7, 2)

  constant = 14 -16 = -2 . . . . subtract 16

The equation can be written as ...

  8y -2 = 2x

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Additional comment

Personally, I prefer standard form, which has common factors removed from the coefficients, and has the constant separated from the variable terms:

  x -4y = -1

Some like the slope-intercept form better:

  y = 1/4x +1/4

Apparently, your curriculum author doesn't care how the equation of the line is written, so we have answered with the same form that was given.

the answer is 48m^2!

step-by-step explanation:

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !