A dog spots a cat 50 feet away and starts to chase it. At the same moment, the cat starts to run away from the dog. The dog is running 12 feet per second and the cat is running 10 feet per second. Let t represent the time elapsed (in seconds) since the chase began. Let d represent the distance between the cat and the dog (in feet) Write a formula to define the distance between them (d) in terms of the time elapsed (t).

D(t) = 50 -2t

At 25 seconds, the dog caught up with the cat

Step-by-step explanation:

At initial time t0

Distance = 50 ft

The dog is running 12 feet per second and the cat is running 10 feet per second.

So for each each time in seconds

Dog covers 12 feet while cat extends by 10 ft .

The distance between them at any given time

D(t)= 50 +10t -12t

D(t) = 50 -2t

The time it will take the dig to get to the cat is what D= 0

D(t) = 50 -2t

0= 50- 2t

2t= 50

t= 25

So at 25 seconds, the dog caught up with the cat

idk

step-by-step explanation:

i don't know

the answer should be a. snail