The equation for a parabola has the form y=ax2+bx+c, where a, b, and c are constants and a≠0. Find an equation for the parabola that passes through the points (−1,8), (2,−4), and (−6,−12).

The equation for the parabola that passes through the points (−1,8), (2,−4), and (−6,−12) is .

Step-by-step explanation:

Let be (−1,8), (2,−4), and (−6,−12) points contained in a parabola, which is represented by a second-order polynomial. To determine the constant of the second-order polynomial, the following system of equations must be solved:

There are several methods for solving this: Equalization, Elimination, Substitution, Determinant and Matrix. The solution of this system is: , and . Hence, the equation for the parabola that passes through the points (−1,8), (2,−4), and (−6,−12) is .

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: